你好,欢迎来到电脑编程技巧与维护杂志社! [免费注册][请登录 杂志社简介广告服务读者反馈编程社区  
合订本订阅
 
 
您的位置:技术专栏 / C专栏
六个变态的Hello Word!(C语言版)
 

下面的六个程序片段主要完成这些事情:

输出Hello, World
混乱C语言的源代码
下面的所有程序都可以在GCC下编译通过,只有最后一个需要动用C++的编译器g++才能编程通过。

hello1.c


01     #define _________ }
02     #define ________ putchar
03     #define _______ main
04     #define _(a) ________(a);
05     #define ______ _______(){
06     #define __ ______ _(0x48)_(0x65)_(0x6C)_(0x6C)
07     #define ___ _(0x6F)_(0x2C)_(0x20)_(0x77)_(0x6F)
08     #define ____ _(0x72)_(0x6C)_(0x64)_(0x21)
09     #define _____ __ ___ ____ _________
10     #include<stdio.h>
11     _____
hello2.c


1     #include<stdio.h>
2     main(){
3       int x=0,y[14],*z=&y;*(z++)=0x48;*(z++)=y[x++]+0x1D;
4       *(z++)=y[x++]+0x07;*(z++)=y[x++]+0x00;*(z++)=y[x++]+0x03;
5       *(z++)=y[x++]-0x43;*(z++)=y[x++]-0x0C;*(z++)=y[x++]+0x57;
6       *(z++)=y[x++]-0x08;*(z++)=y[x++]+0x03;*(z++)=y[x++]-0x06;
7       *(z++)=y[x++]-0x08;*(z++)=y[x++]-0x43;*(z++)=y[x]-0x21;
8       x=*(--z);while(y[x]!=NULL)putchar(y[x++]);
9     }
hello3.c

01     #include<stdio.h>
02     #define __(a) goto a;
03     #define ___(a) putchar(a);
04     #define _(a,b) ___(a) __(b);
05     main()
06     { _:__(t)a:_('r',g)b:_('$',p)
07       c:_('l',f)d:_(' ',s)e:_('a',s)
08       f:_('o',q)g:_('l',h)h:_('d',n)
09       i:_('e',w)j:_('e',x)k:_('\n',z)
10       l:_('H',l)m:_('X',i)n:_('!',k)
11       o:_('z',q)p:_('q',b)q:_(',',d)
12       r:_('i',l)s:_('w',v)t:_('H',j)
13       u:_('a',a)v:_('o',a)w:_(')',k)
14       x:_('l',c)y:_('\t',g)z:___(0x0)}
hello4.c


1     int n[]={0x48,
2     0x65,0x6C,0x6C,
3     0x6F,0x2C,0x20,
4     0x77,0x6F,0x72,
5     0x6C,0x64,0x21,
6     0x0A,0x00},*m=n;
7     main(n){putchar
8     (*m)!='\0'?main
9     (m++):exit(n++);}
hello5.c


01     main(){int i,n[]={(((1<<1)<<(1<<1)<<(1<<
02     1)<<(1<<(1>>1)))+((1<<1)<<(1<<1))), (((1
03     <<1)<<(1<<1)<<(1<<1)<<(1<<1))-((1<<1)<<(
04     1<<1)<<(1<<1))+((1<<1)<<(1<<(1>>1)))+ (1
05     <<(1>>1))),(((1<<1)<<(1<<1)<<(1<<1)<< (1
06     <<1))-((1<<1)<<(1<<1)<<(1<<(1>>1)))- ((1
07     <<1)<<(1<<(1>>1)))),(((1<<1)<<(1<<1)<<(1
08     <<1)<<(1<<1))-((1<<1)<<(1<<1)<<(1<<(1>>1
09     )))-((1<<1)<<(1<<(1>>1)))),(((1<<1)<< (1
10     <<1)<<(1<<1)<<(1<<1))-((1<<1)<<(1<<1)<<(
11     1<<(1>>1)))-(1<<(1>>1))),(((1<<1)<<(1<<1
12     )<<(1<<1))+((1<<1)<<(1<<1)<<(1<<(1>>1)))
13     -((1<<1)<<(1<<(1>>1)))),((1<<1)<< (1<<1)
14     <<(1<<1)),(((1<<1)<<(1<<1)<<(1<<1)<<(1<<
15     1))-((1<<1)<<(1<<1))-(1<<(1>>1))),(((1<<
16     1)<<(1<<1)<<(1<<1)<<(1<<1))-((1<<1)<< (1
17     <<1)<<(1<<(1>>1)))-(1<<(1>>1))), (((1<<1
18     )<<(1<<1)<<(1<<1)<<(1<<1))- ((1<<1)<< (1
19     <<1)<<(1<<(1>>1)))+(1<<1)), (((1<<1)<< (
20     1<<1)<<(1<<1)<< (1<<1))-((1<<1)<< (1<<1)
21     <<(1<<(1>>1)))-((1<<1) <<(1<< (1>>1)))),
22     (((1<<1)<< (1<<1)<<(1<<1)<< (1<<1))- ((1
23     <<1)<<(1<<1)<<(1<<1))+((1<<1)<< (1<<(1>>
24     1)))), (((1<<1)<<(1<<1) <<(1<<1))+(1<<(1
25     >>1))),(((1<<1)<<(1<<1))+((1<<1)<< (1<<(
26     1>>1))) + (1<< (1>>1)))}; for(i=(1>>1);i
27     <(((1<<1) <<(1<<1))+((1 <<1)<< (1<<(1>>1
28     ))) + (1<<1)); i++) printf("%c",n[i]); }
hello6.cpp

下面的程序只能由C++的编译器编译(比如:g++)

01     #include <stdio.h>
02     #define _(_) putchar(_);
03     int main(void){int i = 0;_(
04     ++++++++++++++++++++++++++++
05     ++++++++++++++++++++++++++++
06     ++++++++++++++++++++++++++++
07     ++++++++++++++++++++++++++++
08     ++++++++++++++++++++++++++++
09     ++++i)_(++++++++++++++++++++
10     ++++++++++++++++++++++++++++
11     ++++++++++i)_(++++++++++++++
12     i)_(--++i)_(++++++i)_(------
13     ----------------------------
14     ----------------------------
15     ----------------------------
16     ----------------------------
17     ----------------i)_(--------
18     ----------------i)_(++++++++
19     ++++++++++++++++++++++++++++
20     ++++++++++++++++++++++++++++
21     ++++++++++++++++++++++++++++
22     ++++++++++++++++++++++++++++
23     ++++++++++++++++++++++++++++
24     ++++++++++++++++++++++++++i)
25     _(----------------i)_(++++++
26     i)_(------------i)_(--------
27     --------i)_(----------------
28     ----------------------------
29     ----------------------------
30     ----------------------------
31     ----------------------------
32     ------i)_(------------------
33     ----------------------------
34     i)return i;}

  推荐精品文章

·2019年12月目录 
·2019年11月目录 
·2019年10月目录
·2019年9月目录 
·2019年8月目录
·2019年7月目录
·2019年6月目录
·2019年5月目录
·2019年4月目录    
·2019年3月目录   
·2019年2月目录   
·2019年1月目录  
·探析云计算下应用软件用户数据安全问题
·地理空间集束线可视化表达

  联系方式
TEL:010-82561037
Fax: 010-82561614
QQ: 100164630
Mail:gaojian@comprg.com.cn

  友情链接
 
Copyright 2001-2010, www.comprg.com.cn, All Rights Reserved
京ICP备14022230号-1,电话/传真:010-82561037 82561614 ,Mail:gaojian@comprg.com.cn
地址:北京市海淀区长春桥路5号6号楼1209室,邮编:100089